Member
Member
zyfb   2012-04-26, 23:39
#1
This is what i want to do
if(.gif file is true)
echo" printfullimage";
else
echo"printdefaultimage";

What is the actual code for this?
Member
Member
zyfb   2012-04-27, 00:57
#2
This is what I have, but still not working. I need help with the if statement.

What I want is to show the full image when is a gif file and show the default size image when is other files.

`
<?php

if(******************************)
{
?>

"> [img]<?php echo [/img]" />

<?php

}

else
{
?>
"><?php printDefaultSizedImage(getImageTitle()); ?>

<?php
}
?>
`
Administrator
Administrator
fretzl   2012-04-27, 05:23
#3
You're looking for something like this:
`if (getSuffix($imageobject->filename) == "gif" {`
Member
Member
zyfb   2012-04-27, 07:47
#4
fretzl, thank you for your help.
Do you think you can help me with the rest of the code?
When I upload the code. only the second code the else statement prints.
Administrator
Administrator
fretzl   2012-04-27, 09:25
#5
I'm not sure where you are using this code.
Of course you have to setup the image object.
`http://www.zenphoto.org/news/zenphotos-object-model-framework#creating-a-new-object`

If it's part of the `next_image()` loop the image object is already setup so then you can try:

`if (getSuffix($_zp_current_image->filename) == "gif" {etc...`
Member
Member
zyfb   2012-04-27, 18:43
#6
It works perfectly thank you Smile
  
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